Algebra Q#8
- Option : A
- Explanation : Let y = a + b, where a∝x and b∝1/x.
Let a = K1x and b=K2/x.
where K1 and K2 are constants.
y = K1 x+ K2/x . .. (i).
Given, y = 6 when x = 4.
6 = K14 + K2/4.
⇒16K1 + K2 = 24 . .. (ii)
Also,
when x = 3 .
⇒10/3 = 3K1 + K2/3
⇒9K1 + K2 = 10 . .. (iii)
From Eqs. (i) and (ii), we get
K1 = 2 and K2 = - 8.
y=2x-8/x .
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