Calendar Questions Q.11
0. What was the day of the week on 16 June, 1999?
- Option : C
- Explanation : 16th June, 1999 = (1900 years + 98 years + period from 1.1.1999 to 16.6.1999)
Now first deal with 1998 complete years; then how many odd days are there in 1998 years?
Odd days in 1600 years = 0
Odd days in 300 years = (5 × 3) = 1
98 years have 24 leap years + 74 ordinary years. Number of odd days in 98 years (24 × 2 + 74) = 122 = 3 odd days.
Now come to calculation of odd days in period from 1.1.1999 to 16.6.1999.167 days = 23 complete weeks plus 6 odd days (this result is obtained by dividing 167 days by 7).Months Jan Feb March April May June Total Odd Days 31 28 31 30 31 16 167
Total number of odd days = (0 + 1 + 3 + 6) = 10 ⇒ 3 odd days
Thus, the day asked in the question is Wednesday
*/?>
*/?>
*/?>
*/?>