Calendar Questions Q.12
0. What will be the day of the week on 16 August, 2010?
- Option : B
- Explanation : 16 August, 2010 = (2000 + 9 years + period 1.1.2010 to 16.8.2010)
Odd days in 2000 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 × 2 + 7 × 1) = 11 odd days
11 can be divided by 7 ⇒ 4 odd daysThe odd days can be calculated for each month separately and then added up. This can save some time in calculation. Such as January has 3 odd days (31 divided by 7 gives remainder of 3 and so on).Months Jan Feb March April May June July Aug Total Odd Days 31 28 31 30 31 16 31 16 228
Now, 228 days = 32 complete weeks + 3 extra days, it means 3 odd days.
Total number of odd days = (0 + 0 + 4 + 4) = 8; it means 1 odd day.
Thus, 16 August, 2010 was Monday.
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