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0. The function f(x) = x3 - 6x2 + 9x + 25 has
a maxima at x= 1 and a minima at x = 3
a maxima at x = 3 and a minima at x = 1
no maxima, but a minima at x = 1
a maxima at x = 1, but no minima
f '(x) = 3(x2-4x+3) f ''(x)=6(x)-12 at x=1, f "(1) at x=3, f ''(3) = +ve
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