Utet Apr 15 Paper1 Q#109

0. In the given bar diagram, the wheat production of a farm (in tonne) from year 2009 to 2014 is shown. Sum of production during 'odd' years is how many times that of the 'even' years?

  • Option : B
  • Explanation : Sum of production during
    odd years (2009, 2011, 2013)
    = 90 + 105 + 75 = 270 tonne.
    Sum of production during even years
    (2010,2012,2014)
    =110 + 130 + 120 = 360 tonne.
    Let the sum of production during odd
    years is x times that of the even years.
    270 = x × 360 => x = 270/360.
    x =0.75

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