Utet Apr 15 Paper1 Q#119
- Option : C
- Explanation : Given, a < b a. b+c>c+a ... (i) and since c > a => c + a> a + b ... (ii) so b+c>c+a>a+b [from Eq. (i) and (ii)]. Hence (b + c)/(a+b+c) > (c + a)/(a+b+c) > (a + b)/(a+b+c)
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